Question

Ifl
a/b + c =
b/C+a=
с/a + b = R and a + b + C + 0, then what can be said about R?
1) O _<R < 0.33
2) 0.33 _< R < 0.66
3) 0.66 _< R <1
4) R >_1​

Answer 1

Answer:

2, 0.33_<R<0.66

Step-by-step explanation:

a/(b+c)=b/(c+a)=c/(a+b)=R....EQ1

a+b+c=0=

a=-b-c

b=-c-a

c=-a-b

using these values in EQ1

(-b-c)/(b+c)=(-c-a)/(c+a)=(-a-b)/(a+b)=R

-(b+c)/(b+c)=-(c+a)/(c+a)=-(a+b)/(a+b)=R

-1=-1=-1=R

R=-1

R>=-1

But if a+b+c=/0

Then,

using componendo and dividendo in each ratio we get

(a+b+c)/(b+c+a+c+a+b)

=1/2=R So option 2