Three coins are tossed together. Find the probability of getting) Exactly one head (ii) At most two heads (iii)At least one head and one tail (iv) No tail
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Answered by
2
Answer:
Hi mate
Step-by-step explanation:
SOLUTION :
GIVEN: Three coins are tossed simultaneously.
When three coins are tossed then the possible outcome will be:
TTT, THT, TTH, THH. HTT, HHT, HTH, HHH.
Total number of outcomes = 8.
(i) Let E1 = Event of getting exactly two heads
Then the outcome variable to E1 is THH, HHT ,HTH.
Number of outcomes favourable to E1 = 3
Probability (E1) = Number of favourable outcomes / Total number of outcomes
P(E1) = ⅜
Hence, probability of getting exactly two head ,P(E1) = ⅜ .
(ii) Let E2 = Event of getting at least two head
Then the outcome variable to E2 is HHT, HTH, HHH ,THH
Number of outcomes favourable to E2 = 4
Probability (E2) = Number of favourable outcomes / Total number of outcomes
P(E2) = 4/8 = ½
Hence, probability of getting at least two head ,P(E2) = ½ .
(iiii) Let E3 = Event of getting At least one head and one tail
Then the outcome variable to E3 is THT, TTH, THH, HTT, HHT, HTH,
Number of outcomes favourable to E3 = 6
Probability (E3) = Number of favourable outcomes / Total number of outcomes
P(E3) = 6/8 = 3/4
Hence, probability of getting At least one head and one tail ,P(E3) = ¾ .
(iv) Let E4 = Event of getting no tails
Then the outcome variable to E4 is HHH
Number of outcomes favourable to E4 = 1
Probability (E4) = Number of favourable outcomes / Total number of outcomes
P(E4) = 1/8
Hence, probability of getting no tails ,P(E4) = ⅛
HOPE THIS ANSWER WILL HELP YOU…
Answered by
1
Answer:
3/8, 7/8, 3/4, 1/7
Step-by-step explanation:
Cases=
HHH
HHT
HTH
THH
HTT
THT
TTH
TTT
i) exactly 1 head= 3/8
ii) almost 2 heads= zero heads + one head + two heads
=1/8+3/8+3/8=7/8
you can also do almost 2 heads= 1-3 heads =1-1/8=7/8
iii) atleast 1 head and 1 tail= 1-(no head+no tail)
=1-(1/8+1/8)=1-2/8=6/8=3/4
iv)no tail= 1 case (HHH)=1/7
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