Question

ifl alpha.beta are zeroes of polynomial p(x)=x^2-5x+6 than find the value of (alpha+beta-3×alpha×beta)=7

please solve i mark it brainleast

Answer 1

here is your answer by Sujeet,
Given polynomial,
x²-5x+6
x²-3x-2x+6
x(x-3)-2(x-3)
(x-2)(x-3)

then,
x-2=0
x=2

again,
x-3=0
x=3

Now,
a+b=-b/a=-(-5)/1=5
ab=c/a=6/1=6

Again,
value of (a+b - 3ab)
(5-3*6)
(5-18)=-13



that's all