Question

Ifp and q are the zeros of the polynomial given below, then the values of
(p + q) and (pq) are :
x2 + 5x + 8​

Answer 1

$Compare \: given \: Quadratic \: polynomial: \\</p><p>x^{2} + 5x + 8 \: with \: ax^{2} + bx + c , \: we \:get$

$a = 1 , b = 5 \: and \: c = 8$

$p \: and \: q \: are \: zeroes \: of \: given \\polynomial$

$i ) Sum \: of \:the \: zeroes = \frac{-b}{a}$

$\implies p + q = \frac{-5}{1}$

$\implies \blue { p + q = - 5 }$

$ii ) Product \: of \:the \: zeroes = \frac{c}{a}$

$\implies p q = \frac{8}{1}$

$\implies \blue { p q = 8}$

Therefore.,

$\red { Value \: of \: p+q} \green { = -5 }$

$\red { Value \: of \: pq} \green { = 8 }$

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