Math, asked by Ankitsingh184, 1 year ago

Ifran and Ishan were painting a wall.Ifran painted the diamond - shaped portion. Ishan painted the rest.What area did each paint

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Answered by HitarthDesai
32
Solution to your question. Hope this helps!!
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Answered by RenatoMattice
42

Answer: Area painted by both Ishan and Irfan are 9.6 cm² and 9.6 cm² respectively.

Step-by-step explanation:

Since we have given that

Length of wall = 4+4=8 m

Width of wall = 1.2+1.2=2.4 m

Area of wall will be

Area=Length\times breadth\\\\Area=8\times 2.4\\\\Area=19.2\ m^2

Since we can see that there are 4 right triangles at the corner:

Base of triangle = 1.2 m

Height of triangle = 4 m

So, Area of 4 triangles is given by

Area=4\times \frac{1}{2}\times 1.2\times 4\\\\Area=9.6\ cm^2

Since Irfan painted the diamond shaped portion:

So, Area Irfan painted is given by

\text{Area of wall - Area of 4 right triangles}\\\\=19.2-9.6\\\\=9.6\ cm^2

Since Ishan painted the rest which is equal to 9.6 cm².

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