ifsinQ=CosQ then find the value of 2 tanQ +cos2Q
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sinQ=cosQ
but sin45°=cos45°
hence Q=45°
now,
2tanQ+cos²Q
= 2(tan45°)+cos²45
=2(1)+(1/√2)²
=2+1/2
=4+1/2
=5/2 ANS:
but sin45°=cos45°
hence Q=45°
now,
2tanQ+cos²Q
= 2(tan45°)+cos²45
=2(1)+(1/√2)²
=2+1/2
=4+1/2
=5/2 ANS:
galat ha bhai
was cos2Q= cos²Q?
then let me correct
done
ok
thanks
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