Question

please give the answer

Answer 1

Solution a.)

$4 {k}^{2} ( {4}^{ - 1} k + 4 {k}^{ - 2}) \\ \\ = 4 {k}^{2} ( \frac{k}{4} + \frac{4}{ {k}^{2} } ) \\ \\ = 4 {k}^{2} ( \frac{ {k}^{3} + 16 }{4 {k}^{2} } ) \\ \\ = {k}^{3} + 16$

Solution b.)

${ (\frac{ {3}^{ - 1} }{ { - 2}^{ - 2} } )}^{2} \\ \\ = {( \frac{ \frac{1}{3} }{ \frac{ 1}{4} } )}^{2} \\ \\ = { (\frac{4}{3} )}^{2} \\ \\ = \frac{16}{9}$