ifx=√a2+b2/√a2+b2+√a2_b2/√a2-b2 show that b2 x2- 2a2x+b2=0
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Answer:
x=
a
2
+b
2
−
a
2
−b
2
a
2
+b
2
+
a
2
−b
2
x=
2
a
2
−b
2
2
a
2
+b
2
⇒a
2
−b
2
=
x
2
+1
2a
2
⇒x
2
=
a
2
−b
2
a
2
+b
2
x
2
+1=
a
2
−b
2
a
2
+b
2
+a
2
−b
2
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