ifx3+√8show that x2+1/x2=34
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Hi ,
It is given that ,
x = 3 + √8 ---( 1 )
1/x = 1/( 3 + √8 )
= ( 3 - √8 ) /[ ( 3 + √8 )(3 - √8 )]
= ( 3 - √8 )/[ 3² - ( √8 )² ]
= ( 3 - √8 ) / ( 9 - 8 )
1/x = 3 - √8 -----( 2 )
Add equations ( 1 ) and ( 2 ) we get ,
x + 1/x = 3 + √8 + 3 - √8
x + 1/x = 6
Do the Square of both sides of above
equation ,
( x + 1/x )² = 6²
x ² + 1/x² + 2 × x × 1/x = 36
x² + 1/x² + 2 = 36
Therefore ,
x² + 1/x² = 36 - 2 = 34
I hope this helps you.
: )
It is given that ,
x = 3 + √8 ---( 1 )
1/x = 1/( 3 + √8 )
= ( 3 - √8 ) /[ ( 3 + √8 )(3 - √8 )]
= ( 3 - √8 )/[ 3² - ( √8 )² ]
= ( 3 - √8 ) / ( 9 - 8 )
1/x = 3 - √8 -----( 2 )
Add equations ( 1 ) and ( 2 ) we get ,
x + 1/x = 3 + √8 + 3 - √8
x + 1/x = 6
Do the Square of both sides of above
equation ,
( x + 1/x )² = 6²
x ² + 1/x² + 2 × x × 1/x = 36
x² + 1/x² + 2 = 36
Therefore ,
x² + 1/x² = 36 - 2 = 34
I hope this helps you.
: )
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