Math, asked by arslaanahmad1190, 7 months ago

(ii) 26 - 1.
8
(ii) x2 -
2
(ii) 32a2r3 - 8b2r3 - 40y3 + b2y3
(ii) 26 - 7x3 - 8.​

Answers

Answered by kishor9321
0

Answer:

(i) In [FeF6]3−, the central metal ion has the oxidation state of +3. It has 3d5 configuration and undergoes sp3d2 hybridization. It contains 5 unpaired electrons and has magnetic moment value of 5.91 B.M.

(ii) In [Ti(H2O)6]3+, the central metal ion has the oxidation state of +3. It has 3d1 configuration and undergoes d2sp3 hybridization. It contains 1 unpaired electron and has magnetic moment value of 1.732 B.M.

(iii) In [Cr(NH3)6]3+, the central metal ion has the oxidation state of +3. It has 3d3 configuration and undergoes d2sp3 hybridization. It contains 3 unpaired electrons and has magnetic moment value of 3.88 B.M.

(iv) In [Ni(H2O)6]2+, the central metal ion has the oxidation state of +2. It has 3d8 configuration and undergoes sp3d2 hybridization. It contains 2 unpaired electrons and has magnetic moment value of 2.83 B.M.

(v) In [Fe(CN)6]4−, the central metal ion has the oxidation state of +2. It has 3d6 configuration and undergoes d2sp3 hybridization. It contains 0 unpaired electrons and has magnetic moment value of 0 B.M.

Step-by-step explanation:

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