+
(ii) (2x - 1)(22
(v) 6z2 - 6 + 5z = 0
ng factorisation:
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(v) 6z2 + 5z - 6
6z2 -9z+ 4z - 6
3z(2z - 3) + 2(2z - 3)
(2z - 3)(z + 2)
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