Question

ii) 4cos ^3 45º - 3cos45° + sin45°​

Answer 1

Answer:

0

Step-by-step explaination:

cos 45 = 1/√2 = sin 45 , so

cos^3 45 = 1/ 2√2 , so

4cos^3 45 = 4 × 1/ 2√2 = 2/ √2

3cos 45 = 3 × 1/ √2 = 3/ √2

So 4cos^ 45 - 3cos 45 + sin45 =

2/ √2 - 3/√2 + 1/ √2 = 2-3+1/ √2 = 0.

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Answer 2

Answer:

4cos ^3 45º - 3cos45° + sin45°

=> 4 x (1/√2) ^3 - 3 x (1/√2) + (1/√2)

=> 4/ 2√2 - 3/√2 + 1/√2

=> (2-3+1) /√2

=> 0 Ans