Question

ii) 4x2 - 16x + 7 vi) x2 – 24x + 63 iii) 3z2 -- 42-4 vii) 9x2 - 40x + 16​

Answer 1

Answer:

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Step-by-step explanation:

Q. Answer the following:-

ii) 4×2-16x+7

ATQ[According to the question]

⇒(4×2)(-16x+7)

⇒(8)(-16x+7){Shifting 7to8} [Sign would be change  +to-]

⇒8-7(-16x)

⇒1(-16x)

⇒x=[-16/1]

⇒x=-16{ans.}

vi)2x-24x+63

ATQ[According to the question]

⇒(2x-24x)+63

⇒(-22x)+63

⇒x=-63\22{ans.}

iii)3z^2-42-4

ATQ[According to the question]

⇒3z^2(-42-4) {Integers Rule (-)(-)=+}

⇒3z^2(-38){ans.}

vii)9z^2-40x+16

ATQ[According to the question]

⇒9z^2(-40x+16)

⇒9z^2(x=-40\16)

⇒9z^2(x=5\2)[ans.]

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