Math, asked by ramaiahd378, 8 months ago

(ii) 6 sides
(i) sides
dhe angle masure in the following figures.
700
polygon on the floor, using a piece of chalk.
(In the figure, a pentagon ABCDE is shown) (Fig 3.8)
We want to know the total measure of angles, i.e.
m21 + m22 + m23 + m24+ m25. Start at A. Walk
along AB. On reaching B. you need to turn through an
angle of m_1, to walk along BC. When you reach at C.
you need to turn through an angle of m2 to walk along
CD. You continue to move in this manner, until you return
to side AB. You would have in fact made one complete turn.
Therefore, mZ1+m22 + m23+ m24+ m25 = 360°
This is true whatever be the number of sides of the polygon.
Therefore, the sum of the measures of the external angles of any polygon is 360°
120°
(b)
Example 1: Find measurer in Fig 3.9.
Solution:
+90° +50° +110° = 360° (Why?)
* + 250° = 360°
I = 110
500
110°
TRY THESE
Take a regular hexagon Fig 3.10.​

Answers

Answered by shdhakarp1977
2

Answer:

the answer is 2567. brainly mate

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