(ii) (998) why this is 998
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Answer:
As per the question,
We have been provided that,
The density of water at 20 °C = 998 kg/m³
The density of water at 40 °C = 992 kg/m³
Therefore,
Change in density, δv = (998 - 992) = 6
And
Change in temperature, δT= (40 - 20) = 20°C
Now,
The coefficient of volume expansion of water is given by
\alpha_{v} = \frac{\delta v}{v} \times \frac{1}{\delta T}α
v
=
v
δv
×
δT
1
Put all the given values in this equation, we get
\alpha_{v} = \frac{6}{998} \times \frac{1}{20}α
v
=
998
6
×
20
1
\alpha_{v} =\frac{6}{998 \times 20}α
v
=
998×20
6
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