(ii) 9x2 + (p + 3)x + 1 = 0
Answers
Answered by
0
Answer:
9 X2 +[p +3]X +1 =0
18 +px+3x+1 =0
px +3x +1= -18
px +3x = -18-1
px +3x = -19
p[x +3x] = -19
Similar questions