(ii) a(a - b) + 25(b + 3)
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Given a,b,c are three numbers between 2 and 18 and a+b+c=25 ...(i)
2,a,b are consecutive terms of A.P, then
so we can write , a=
2
(b+2)
...(ii)
also given b,c,18 are consecutive terms of a GP
so it implies c
2
=18b...(iii)
From equations (i), (ii) and (iii), we get
b=8 and 32 , since b is between 2 and 18 , therefore taking b=8
and then taking the value of b and putting it in other 2 equations we get the values of a=5 and c=12
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