(ii) a+b+c= 6, a2 +b2+c2 =14 then ab+bc+ca
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Since (a+b+c)²=a²+b²+c²+2(ab+bc+ca)
=> (6)²=14+2(ab+bc+ca)
=>36-14=2(ab+bc+ca)
=>22=2(ab+bc+ca)
=>ab+bc+ca=11
Hope it is helpful.
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