(ii) A horizontal pipe of non-uniform bore has water flowing through it such that the velocity of flow is 40 cm/sec at a point where pressure is 2 cm of mercury column. What is the pressure at a point where the velocity of flow is 60 cm/sec? (Take g-980 cm/sec² and density of water = 1 gm/cc)
Answers
Answered by
0
Answer:
Correct option is
C
37.5
Using the bernoulli's therom,
P
1
+
2
1
pV
1
2
=P
2
+
2
1
pV
2
2
⇒40×10
3
+
2
1
×500×4=P
2
+
2
1
×1000×9
⇒40×10
3
+2000−45000=P
2
⇒37.5×10
3
Pa=P
2
⇒P
2
=37.5kPa
Answered by
1
Answer:
correct option = c
Explanation:
37.5
Using the bernoulli's therom,
P
1
+
2
1
pV
1
2
=P
2
+
2
1
pV
2
2
⇒40×10
3
+
2
1
×500×4=P
2
+
2
1
×1000×9
⇒40×10
3
+2000−45000=P
2
⇒37.5×10
3
Pa=P
2
⇒P
2
=37.5kPa
I hope it helps you
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