Question

(ii) A metal sphere 30cm in radius is positively charged with 2 PC. Find the potential
(a) at the centre of the sphere.
(b) on the surface of the sphere,​

Answer 1

Answer:

30 cm

Explanation:

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Answer 2

Concept

A potential is either the scalar or vector potential. It is a field defined in space in either scenario, from which many significant physical properties can be deduced.

Given

A metallic sphere is given whose radius is $30cm$ and the positive charge on it is $2pc$.

Find

We have to find the potential at the center of the sphere and the potential on the surface of the sphere.

Solution

The radius is $r=30cm$ and

positively charged $q=2\times 10^{-12}$.

Firstly, we will find the potential on the surface of the sphere.

$\begin{aligned}V&=\frac{1}{4\pi \epsilon_{0}}\times \frac{q}{r}\\ &=9\times 10^{9}\times \frac{2\times 10^{-12}}{30\times 10^{-2}}\\ &=6\times 10^{-2}V\end{aligned}$

Now, we will find the potential at the centre of the sphere.

Thus, the potential at any point inside the sphere will be equal to the potential at the surface.

The potential at the centre of the sphere we find is,

$V=6\times 10^{-2}V$

Hence, the potential at the centre of the sphere and the potential on the surface of the sphere is $V=6\times 10^{-2}V$.

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