Question

(ii) A peacock is sitting on the tree and observes its prey on
the ground. It makes an angle of depression of 22° to
catch the prey. The speed of the peacock was observed to
be 10 km/hr and it catches its prey in 1 min 12 seconds.
At what height was the peacock on the tree?
(cos 22° = 0.927, sin 22° = 0.374, tan 22° = 0.404)​

Answer 1

Answer:

                                         

Step-by-step explanation:                              

• CONSIDER Δ ABC , RIGHT ANGLED AT B.

THEREFORE HEIGHT OF THE TREE = AB. AND DISPLACEMENT BETWEEN PEACOCK AND IT'S PREY = AC.

• CONVERTING  10 KM/HR INTO M/S

     10 KM/HR = 10 * 5 / 18 = 25 / 9 M/S.

    1 MIN 12 SECOND = 72 SEC.

• SPEED = DISTANCE / TIME.

        25 / 9 = AC / 72

          225 METRE = AC

• SIN 22° = AB / AC

     0.374 = AB / 225

      225 * 0.374 = AB

       84.150 METRE = AB

• PEACOCK WAS SITTING AT THE HEIGHT OF 84.150 METRE .