Question

ii) A relation between a and b such that point (a,b) is
equidistant from the points (8,3) and (2,7), is
[1]
(a) 3a - 2b = 4
(b) 3a - 2b = 5
(c) 3a + 2b = 4
(d) None of these

iv) If PQ || BC andAP/PB=3/5
then AC such that AQ =2.1 cm,
is equal to

(a) 5.2 cm
(c) 5.8 cm
(b) 5.4 cm
(d) 5.6 cm​

Answer 1

five point two centimiter

Answer 2

Answer:

well come...

Step-by-step explanation:

im fine dear what about uh???