Question

ii) A TV tower has a height of 200 m.
How much population is covered by TV
transmission if the average population
density around the tower is 1000/km?​

Answer 1

Answer:

81.67 * 10 ^12

Explanation:

d=sqrt(2*6.4*10^6*200)

d=5.1*10^6

area = 3.14*d^2

Answer 2

The population covered by TV  transmission is $=8.0\times10^6$.

Explanation:

The coverage range is given as

$d=\sqrt{2Rh}$

Here, R is the radius of the earth and h is the height of the TV tower.

Given h = 200 m and we know R = 6400 km.

Substitute the values, we get

$d=\sqrt{2\times6.4\times10^6m\times200m}$

$d=50.6\times10^3m$.

Area of reach,

$A=\pi d^2$

so, $A=3.14\times(50.6\times10^3m)^2$

$A=8.0\times10^9m^2$

The population covered = Area of reach x population  density.

Given population  density = 1000 /km^2

Therefore,

The population covered =

$= 8.0\times10^3km^2\times1000/km^2$

$=8.0\times10^6$

Thus population covered by TV  transmission is $=8.0\times10^6$

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