Question

(ii) Complete the following activity to find 30th term of the A.P.
3, 8, 13, 18, ... .
Here, a = 3, d = 0 30th term means tzo = ?
tn
=
... (Formula)
.. t30 = 3 +
. (Substituting the values)
.. 130 = 3 + 29 x 5
... t30​

Answer 1

Answer:

A.P. = 3, 8, 13, 18..

Here,

a = 3

d = a² - a¹ = 8 - 3 = 5

A₃₀ = ?

Using AP formula,

An = a + (n - 1) d

A₃₀ = 3 + (30 - 1) 5

A₃₀ = 3 + (29) 5

A₃₀ = 3 + 145

A₃₀ = 148

Hence, the 30th term of AP 3, 8, 13, 18.. is 148.

Answer 2

The 30th term of given AP 3, 8, 13, 18,... is 148.

Given:

• AP 3, 8, 13, 18,...

To find:

• Find the 30th term.

Solution:

Formula to be used:

General term of A.P.: $\bf a_n = a + (n - 1)d$

here a: first term

d: Common difference

n: no. of terms

Step 1:

Write the terms used in the formula.

a= 3

d= 8-3= 5

n= 30

Step 2:

Put the values in the formula.

$a_{30} = 3 + (30 - 1)5$

or

$a_{30} = 3 + (29 \times 5)$

or

$a_{30} = 3 + 145$

or

$\bf a_{30} = 148$

Thus,

30th term of A.P. is 148.

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