(ii) Eu and Yb prefer to exhibit +2 oxidation state.
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Eu and Yb shows +2 oxidation state bcz by loosing two electrons these will get stable half filled 4f7 and fully filled 4f14 configuration i.e.
Eu+2= 4f7 and Yb+2= 4f14.......
hope it will help you.....
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