Question

(ii) Evaluate (99)3 using identities.​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

$99^3$

$=(100-1)^3$

Now we know that :

$(a-b)^3=a^3-3a^b+3ab^2-b^3$

Substituting a and b as 100 and 1 respectively:

$=(100-1)^3=100^3-3(100)^2(1)+3(100)(1)^2-1^3$

$=1000000-30000+3000-1$

$=972999$