Math, asked by aravind8093, 9 months ago

(ii)Expand using identity(2x-3y)3​

Answers

Answered by dwivediharsh2006
0

(2x-3y)^3

(a-b)^3=a^3-b^3-3ab(a-b)

=

(2x)^3-(3y)^3-3*2x*3y(2x-3y)

=8x^3-27y^3-18xy(2x-3y)

=8x^3-27y^3-36x^2y+54xy^2

Answered by AryaPriya06
1

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