Question

ii) Factorise 4d? +62 +62 - 4ab +2bc - 4ca using identity.
far, we have dealt with identities involving second degree terms​

Answer 1

solution

Factor 4d+62+62−4ab+2bc−4ca

−4ab−4ac+2bc+4d+124

=2(−2ab−2ac+bc+2d+62)

Answer:

2(−2ab−2ac+bc+2d+62)