ii) Factorise 4d? +62 +62 - 4ab +2bc - 4ca using identity.
far, we have dealt with identities involving second degree terms
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Factor 4d+62+62−4ab+2bc−4ca
−4ab−4ac+2bc+4d+124
=2(−2ab−2ac+bc+2d+62)
Answer:
2(−2ab−2ac+bc+2d+62)
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