Question

ii] Find diagonal of a square whose side is 10 cm​

Answer 1

Step-by-step explanation:

side of square is 10 cm

In right angled △ABD

AB

2

+AD

2

=BD

2

[according to Pythagoras theorem]

(10)

2

+(10)

2

=BD

2

$

100+100=BD

2

BD

2

=200

BD=10

2

cm

∴ Diagonal of square =10

2

cm..

Hope it's help

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Answer 2

Step-by-step explanation:

let diagonal be x

by using Pythagoras thm,

10^2 + 10^2 = x^2

200 = x^2

$x = 10 \sqrt{2}$