(ii) Five years ago, Nuri was thrice as old as Sonu. Ten years later, Nuri will be twice as
old as Sonu. How old are Nuri and Sonu?
(iii) The sum of the digits of a two-digit number is 9. Also, nine times this number is
twice the number obtained by reversing the order of the digits. Find the number.
0000 She asked the cashier to give her
Answers
(ii) Let the age of Nuri be x and that of Sonu be y.
Given,
(x−5)=3(y−5)
3y−x=10 ..... (1)
And,
(x+10)=2(y+10)
2y−x=−10 ....(2)
Subtracting (2) from (1), we get
y=20
Substituting value of y in (1)
60−x=10
x=50
Hence, the ages of Nuri and Sonu are 50 and 20 respectively.
thank you
Given : Five years ago, Nuri was thrice as old as Sonu. Ten years later, Nuri will be twice as old as Sonu
To Find : . How old are Nuri and Sonu?
Solution:
Nuri = N
Sonu = S
Five years ago, Nuri was thrice as old as Sonu.
=> N - 5 = 3 (S - 5)
=> N - 5 = 3S - 15
=> N = 3S - 10
Ten years later, Nuri will be twice as old as Sonu
N + 10 = 2(S + 10)
=> N + 10 = 2S + 20
=> N = 2S + 10
3S - 10 = 2S + 10
=> S = 20
=> N = 50
Nuri is 50 Years old
Sonu is 20 Year old
The sum of the digits of a two-digit number is 9. Also, nine times this number is twice the number obtained by reversing the order of the digits. Find the number.
A + B = 9
9 (10A + B) = 2 (10B + A)
=> 90A + 9B = 20B + 2A
=> 88A = 11B
=> B = 8A
=> A + 8A = 9
=> A = 1
=> B = 8
18 is the number
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