Question

(ii) If tan A = 3/4 find the value of sin 2A.​

Answer 1

⭐Solution ⭐

✏given here

TanA = 3/4....(1)

so,

Sin A = 3/√(3²+4²)

= 3/(√9+16)

= 3/5

And,

Cos A= √( 1-Sin²A)

= √[ 1-(3/5)²]

= √[ 1-9/25]

= 4/5

So,

we know,

Sin2A= 2 SinA Cos A

= 2×(3 /5)×(4/5)

= 24/25

✏Hopes its help's u

✏Marks Brainliest.

Answer 2

Solution→

tan A = 3/4

We have to find sin2A

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Now we know that →

Sin 2A = 2 tan A / 1- tan²A

As tan A is already given to us . So, putting the value of tan A in the given formula

Calculation →

$\sin(a) = \frac{2( \frac{3}{4} )}{1 + ( { \frac{3}{4}) }^{2} }$

$\sin(a) = \frac{ \frac{3}{2} }{ 1 + \frac{9}{16} }$

$\sin(a) = \frac{ \frac{3}{2} }{ \frac{25}{16} }$

$\sin(a) = \frac{3}{2} \times \frac{25}{16}$

$\sin(a) = \frac{24}{25}$

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So , sin2A = 24/25

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hope it helps