(ii) (k - 4)x2 + 2(k - 4)x + 4 = 0
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(k-4)x²+2(k-4)x+2=0
IF BOTH THE ROOTS ARE EQUAL;
THEN DISCRIMINANT ⇒b²=4ac.
then a=k-4; b=2(k-4) ;c=2; substituting the values.
(2k-8)²=4×(k-4)×2
4k²+64-32k=8k-32
4k²-40k+96=0
k²-10k+24=0
(k-4)(k-6)=0
k=4,6
❤️☺________️☺__________☺❤️
✌
ⓕ尺ⓘⒺⓝđ ☺☝
*•.¸❤️☺_____️☺_______☺❤️¸.•*
(k-4)x²+2(k-4)x+2=0
IF BOTH THE ROOTS ARE EQUAL;
THEN DISCRIMINANT ⇒b²=4ac.
then a=k-4; b=2(k-4) ;c=2; substituting the values.
(2k-8)²=4×(k-4)×2
4k²+64-32k=8k-32
4k²-40k+96=0
k²-10k+24=0
(k-4)(k-6)=0
k=4,6
❤️☺________️☺__________☺❤️
✌
ⓕ尺ⓘⒺⓝđ ☺☝
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