Math, asked by madhu5839, 11 months ago

(ii) (k - 4)x2 + 2(k - 4)x + 4 = 0​

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Answered by nosumittiwari3
28
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(k-4)x²+2(k-4)x+2=0
IF BOTH THE ROOTS ARE EQUAL;

THEN DISCRIMINANT ⇒b²=4ac.

then a=k-4; b=2(k-4) ;c=2; substituting the values.

(2k-8)²=4×(k-4)×2

4k²+64-32k=8k-32

4k²-40k+96=0

k²-10k+24=0

(k-4)(k-6)=0

k=4,6

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Answered by UtkarshG
21

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