Question

ii) kx +3y+1=0, x+2y+1=0, x+y=0)
find value of k
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Answer 1

Answer:

2

Step-by-step explanation:

At first late find the value of x,

x+y=0

=> x= -y

by putting the value of x we find,

(-y)+2y+1=0

=> y+1=0

=> y = -1

now lets put it together,

k(-y)+3y+1= 0

=> k.1+ 3(-1)+1=0

=> k-3+1=0

=> k-2=0

so, K =2