Question

(ii) Median value by the following data is :
16, 8, 5, 10, 8, 20, 14,4, 12
(a) 8
(b) 10
(C) 12
(d) 20​

Answer 1

Answer:

Converting the given data into frequency distribution table

Group Frequencies

(f) Cf

6-8 12 12

8-10 20 32

10-12 16 48

12-14 15 63

14-16 17 80

16-18 8 88

18-20 12 100

Σf=100

Here, N=100

Hence the median class =

2

N

=

2

100

=50

In the above table 12-14 is the median class and the respective cf is 20 (nearest to the value of 50)

Acc to ques, l

1

=12 (lower limit of median class)

CF=48 (C= cumulative frequency preceding the median class)

i=l

2

−l

1

=2 (width of class interval of median class)

f = 15 (frequency of median class)

Median=l

1

+

f

2

N

−C

×i=12+

15

50−48

×2

Median= 12.266 (B)

Answer 2

Answer:

b) 10

Additional information:

The median is the middle number in a sorted, ascending or descending, list of numbers and can be more descriptive of that data set than the average.

If there is an odd amount of numbers, the median value is the number that is in the middle, with the same amount of numbers below and above.

If there is an even amount of numbers in the list, the middle pair must be determined, added together, and divided by two to find the median value.

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