Question

(ii) s-t=3
s/3+ t/2=6
by substitution method
​

Answer 1

Answer: Image below

Sorry about the handwriting

Answer 2

Answer:

2. s-t=3....1 s/3 +s/2=6......2 from eq 1 we get, s=3+t Putting this value of s in eq 2 . 3+t/3 + t/2 = 6 6+2t+3t/6=6 6+5t=6×6 6+5t=36 5t =36-6 5t=30 t=6 now ,substituting this value of t in eq1 s-6=3 s=3 + 6 s=9