Question

(ii) sec2 45º – cot? 4
Let us determine the values of:
(i) sind 45° - cosec2 60° + sec2 30°
(ii) 3tan 45º - sinº 60°
(
3
4
10 - cot 30° – sec2 45°
(iv) cot 30°+3 sin? 60°_2cosec? 60°
3
tan? 30°
4
cos30°
+
(vi) cot 30° – 2cos? 60° – se
(1) Isin45
sin45° cos30°
tan60°
?
2
2tan30°cosec60°
(vii) sec? 60° - cot? 30° -
1+tan230°
tan60°-tan30°
+ cos 60°cos 30° + sin 60° sin 30
1+tan60°tan30°
230°
cos260°+cos 30°
= (sin 60° tan 30°)​

Answer 1

Step-by-step explanation:

very long question it will surely take 2 hr.