Question

(ii) Show that the function f: R → R given by f(x) = ax + b, where a, b E R, a is not equal to 0 is a bijection​

Answer 1

Answer:

Step-by-step explanation:

Given function f : R → R is such thatfx = ax+b a b ∈ R a ≠ 0Therefore fx is an onto function.As fx is both one-one and onto so it is a bijective function.