Question

(ii) sin 2A = 2 sin A is true when A=
(A) 0° (B) 30°
C) 45°
(D) 60°​

Answer 1

Answer:

Step-by-step explanation:

By formula

sin2A =  2sinAcosA

therefore

=>2sinAcosA = 2sinA

( 2sinA gets cancelled from both sides )

=> cosA = 1

=>cosA = cos0

=> A=0

Answer 2

Answer:

A)-0°

Step-by-step explanation:

Out of the given alternatives, only A = 0° is correct

As

sin 2A = sin 0° = 0

2 sin A = 2sin 0° = 2(0) = 0

Hence, (A) is correct

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