Question

(ii) sin 42° sec 48° + cos 42° cosec 48° = 2​

Answer 1

If a+b = 90 then
sin a . Sec b = 1
Cos a. Cosec b = 1
Tan a. Tan b =1
Cot a cot b = 1
Prove
Sin a . 1/ cos b Where b is (90-a)
Sin a . 1/ cos (90-a )
Sin a . 1/ sin a = 1

So
1 + 1 = 2

Answer 2

Answer:

sin 42° sec 48° + cos 42° cosec 48° = 2

Sin 42° cosec 42° + cos 42°+ sec 42°

= 1+ 1 = 2