Question

II. Solve:
1. A constant force acts on an object of mass 10 kg for a duration of 4 s. It
Increases the object's velocity from 2 m s' to 8 ms. Find the magnitude of the applied
force.​

Answer 1

Explanation:

m=10kg

t=4sec

u=2m/s

V=8m/s

a=v-u/t

8-2/4

1.5m/s^2

f=m.a

10kg × 1.5 m/^2

=15N