Question

(ii) tan (55° -0) - cot (35° + 0) =​

Answer 1

Step-by-step explanation:

$\tan(55 - \alpha ) - \cot(35 + \alpha ) \\ \tan(55 - \alpha ) - \ \cot (90 - (55 - \alpha )) \\ \tan(55 - \alpha ) - \tan(55 - \alpha ) = 0$