(ii) tan x +tan 2x + tan x tan 2x = 1
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Solution : We have to find x.
Now, tanx + tan2x + tanx tan2x = 1
⇒ tanx + tan2x = 1 - tanx tan2x
⇒ (tanx + tan2x)/(1 - tanx tan2x) = 1
⇒ tan(x + 2x) = tan(π/4)
⇒ 3x = π/4
⇒ x = π/12
∴ the required solution is x = π/12.
Trigonometric rules :
tan(A + B) = (tanA + tanB)/(1 - tanA tanB)
tan(π/4) = 1
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