(ii) tan-'x - tan-' y = tall
1 + xy
1)>; , y
xy > 1; x, y>0
(iii) tan-'r + tan- y = 1 + tan-
1- ху
Answers
Answered by
0
Answer:
what it is I don't understand sorry
Answered by
0
Answer:
Let α=tan
−1
x,β=tan
−1
y
As tan(α+β)=
1−tanαtanβ
tanα+tanβ
⇒tan(α+β)=
1−xy
x+y
⇒α+β=tan
−1
(
1−xy
x+y
)= tan
−1
x+tan
−1
y
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