(ii) The focal length of concave mirror is 25 cm and image formed at 35 cm and find the
position of object and write the nature of image formed.
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Answer:
Given,
Focal length, f=−30 cm if u=−x
real ⇒ same side ⇒v=−ve
Magnification, m= uv ⇒v=m×u=3×(−x)=−3x
From mirror formula, f1 = v1 + u1
We get −301 = −3x1 + −x1
⇒ 301 = 3x 1+3
⇒ 43x =3⇒x=40 cm
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