ii) The perimeter of a ∆ABC is 12 cm and its
inradius is 1 cm. Then find its area.
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It is given that the inradius is 1 cm and the perimeter is 12 cm.
Let the lengths of the sides be a,b and c cm.
⇒a+b+c=16.
⇒ The area of the triangle =1a/2+1b/2+1c/2=1(a+b+c)/2=1×16=16 cm sq.
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