Question

(ii) The volume occupied by 80 g of carbon dioxide at STP.

Answer 1

Answer:

40.75 l

Step-by-step explanation:

ideal gas equation ,

Pv = nRT

At STP ,

P= 1atm , v = ? , n = 80/44 , R = 0.0821 , T = 273K

$1 \times v \: = \frac{80}{44} \times 0.0821 \times 273 \\ v = 1.818 \times 0.0821 \times 273 \\ v = 40.75l$

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