Question

(ii) The zeroes of the polynomial f(x) = x2 – 2x – 3 are
(1) 1,3
(2) -1, -3
(3) -1,3
(4) 1, -3
C
1​

Answer 1

x+1=0

x=0-1

x=-1

(-1)2 - 2(-1) - 3

-2+2-3

-2-1

-3

so, answers are -1 and -3

Answer 2

Answer:

${x}^{2} - 2x - 3 \\ {x}^{2} - (3 - 1) - 3 \\ {x}^{2} - 3x + x - 3 \\ x(x - 3) + 1(x - 3) \\ (x - 3)(x + 1) \\ if(x - 3) = 0 \\ x = 3 \\ if(x + 1) = 0 \\ x = - 1 \\ x = (3 \: and \: - 1)ans.$