Question

(ii) With the help of the flowchart given below solve the equation x^2 +2√5x+5 -0
using the
formula :
-->Find the values of
a, b, c by comparing
x2 + 2√5x + 5 = 0
with ax^2 + bx+c=0
-->Find the value of
b^2 - 4ac
-->Write the formula
for solving
quadratic
equation
-->Substitute the values in the formula and
solve.​

Answer 1

Answer:

Step-by-step explanation:

Given equation is x^2 + 2√5x + 5= 0

Here a= 1, b = 2√5, c = 5

D = b^2 - 4ac = (2√5)^2 - 4×1×5 = (2^2 × √5^2) - 20 = (4 × 5) - 20 = 20 -20 = 0

General form of the quadratic equation is ax^2+ bx + c = 0

x = - b ± √ b^2 - 4ac /2a = -( - 2√5) ± √0 / 2× 1

= 2√5 ± 0/2 = 2√5 ± 0 = 2√5 is the answer.