(ii) (x + 3) (x - 3) (x + 4) (x - 4)
Answers
Answer:
sooo what we do ? expand or any thing
Answer:
(x+3)(x−3)(x+4)(x−4)=x
4
−25x
2
+144
Step-by-step explanation:
\begin{gathered}(x+3)(x-3)(x+4)(x-4)\\=[(x+3)(x-3)][(x+4)(x-4)]\\=(x^{2}-3^{2})(x^{2}-4^{2})\end{gathered}
(x+3)(x−3)(x+4)(x−4)
=[(x+3)(x−3)][(x+4)(x−4)]
=(x
2
−3
2
)(x
2
−4
2
)
\begin{gathered} By \: algebraic \: identity :\\\boxed {(a+b)(a-b) = a^{2}-b^{2}}\end{gathered}
Byalgebraicidentity:
(a+b)(a−b)=a
2
−b
2
= (x^{2}-9)(x^{2}-16)=(x
2
−9)(x
2
−16)
\begin{gathered}=x^{2}(x^{2}-16)-9(x^{2}-16)\\=x^{4}-16x^{2}-9x^{2}+144\\=x^{4}-25x^{2}+144\end{gathered}
=x
2
(x
2
−16)−9(x
2
−16)
=x
4
−16x
2
−9x
2
+144
=x
4
−25x
2
+144
Therefore,
(x+3)(x-3)(x+4)(x-4)=x^{4}-25x^{2}+144(x+3)(x−3)(x+4)(x−4)=x
4
−25x
2
+144
Step-by-step explanation:
Hope it helps you. Mark as brainliest