Question

ii) x(x-1) = (x+2)(x-3)​

Answer 1

Step-by-step explanation:

$x(x - 1) = ( x + 2)(x - 3) \\ \\ x {}^{2} - x = x { }^{2} - 3x + x {}^{2} - 6 \\ \\ 2x = x {}^{2} - 6 \\ \\ x {}^{2} - 2x - 6 = 0$

Answer 2

Answer:

no solution

Step-by-step explanation:

x(x - 1) = (x + 2)(x - 3) -Given

x^2 - x = x^2 - 3x + 2x -6 -Distributive Property

x^2 - x = x^2 -x - 6 -Simplify

x^2 - x^2 - x + x = x^2 - x^2 - x + x - 6 -Addition and Subtraction Properties

everything cancels out = 6

there is no solution to this problem